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SQLite update query Android

The table contains 4 columns : rowID , word , defintition , group_id

I want to change a certain row's word and definition . So here is my code (word is an object where the word , definition , id and the group_id are stored)

  ContentValues values = new ContentValues(); 
    values.put(KEY_WORD, word.getWord());
    values.put(KEY_DEFINITION, word.getDefinition());
    db.update(TABLE_WORDS, values, KEY_ID, new String [] {String.valueOf(word.getID())});

Can anyone tell me why it only creates a new line instead of changing the row under given ID ?

SQLiteDatabase db = this.getWritableDatabase();

        ContentValues values = new ContentValues();
        values.put(KEY_NAME, contact.getName());
        values.put(KEY_DATE, contact.getDate());

        // updating row
        return db.update(TABLE_CONTACTS, values, KEY_ID + " = ?",
                new String[] { String.valueOf(contact.getID()) });
   String id = "1";
   SQLiteDatabase db = this.getWritableDatabase();
    ContentValues values = new ContentValues();
    values.put(COLUMN_NOTIFICATION_STATUS,"canceled");
    db.update(TABLE_NOTIFICATION, values,COLUMN_NOTIFICATION_ID + " = ? ",new String[]{ String.valueOf(id) });

it will work as prepared statement. this piece of code worked in my case .. Thanks

@Digvesh has the right idea, but because of this limitation , converting an int to a String to use as a selection arg will not work properly. Instead do this:

// assume: SQLiteDatabase db = this.getWritableDatabase();

ContentValues values = new ContentValues();
values.put(KEY_WORD, word.getWord());
values.put(KEY_DEFINITION, word.getDefinition());
int rowsUpdated = db.update(TABLE_WORDS, values, KEY_ID + "=" + word.getID(), null);

this work for me, while db.rawquery didnot work.

output query

 String qu="UPDATE "+ DATABASE_TABLE_DATA + " SET "+isbookmark+" = "+status+" WHERE id = "+uid+";"; db.execSQL(qu); output query : UPDATE tabel_data SET `isbookmark` = 1 WHERE id = 2720271; 

Use LIKE instead of = operator.

SQLiteDatabase db = this.getWritableDatabase();

        ContentValues values = new ContentValues();
        values.put(KEY_NAME, contact.getName());
        values.put(KEY_DATE, contact.getDate());

        // updating row
        return db.update(TABLE_CONTACTS, values, KEY_ID + " LIKE ?",
                new String[] { String.valueOf(contact.getID()) });

使用此链接 ,它将帮助您更新SQLite数据库中的查询

You can try this using db.rawQuery , ie

db.rawQuery("UPDATE "+ TABLE_WORDS + " SET "+ KEY_WORD + " = '"+word.getWord()+"' ,"+KEY_DEFINITION+"= '"+word.getDefinition()+ "' WHERE " + KEY_ID + " = "+word.getID(), null);

Here you don't need to create any ContentValues .

here and here are details

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