I want to get my viewport & screen width & height values to PHP. I found this link ( http://css-tricks.com/screen-resolution-notequalto-browser-window/ ) after quite much googleing.
I tried to apply it with the code below but my issue is I am not redirected to body.php after execution of index.html so I can't get any POST
value from index.html to body.php . I am sure that jquery.js is loaded. I also tried the script in header part after jquery.js .
It seems that I couldn't achieve to make a proper request.
I know nothing about javascript or AJAX coding unfortunately. I don't want to use google analytics api.
I am using XAMPP for PHP execution.
Can you please kindly clarify where I am wrong with correctness suggestion? thanks all
My codes:
for index.html
<!DOCTYPE HTML>
<html>
<head>
<meta charset=utf-8>
<title>my title</title>
<!-- latest jquery library -->
<script src="js/jquery.js"></script>
</head>
<body>
<script>
$.ajax({
type: "POST",
url: "http://localhost/public_html/body.php",
data: {
width : $(window).width(),
height : $(window).height(),
screen_width : screen.width,
screen_height: screen.height
}
});
</script>
</body>
</html>
for body.php
<?php
echo 'check print'.'<br />';
echo $_POST['width'].'<br />';
echo $_POST['height'].'<br />';
echo $_POST['screen_width'].'<br />';
echo $_POST['screen_height'].'<br />';
?>
you need to wait until the document is ready before trying to execute your script.
$(function(){
$.ajax({
url: 'http://localhost/public_html/body.php',
type: 'POST',
dataType: 'html',
data: {
width : $(window).width(),
height : $(window).height(),
screen_width : screen.width,
screen_height: screen.height
}
})
.done(function(response) {
alert(response);
})
.fail(function(error) {
alert(error);
})
.always(function() {
console.log("complete");
});
});
Check maybe console for ajax same origin error. My google version doens't allow ajax on localhost until forced explicitly.
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