object instantiation in c++

Question

In C++ is it true that if you instantiate an object of a class, that for every object all of methods of the class are copied for the new object?

I tried to point to a method of a class with two different objects, but I'd problems with pointer to member.

Any idea?

Answer 1

In C++ is it true that if you instantiate an object of a class, that for every object all of methods of the class are copied for the new object?

No, member functions are not usually copied anywhere. A different implicit parameter this is instead passed to any non-static member function, for each object of that class-type.

Answer 2

No, that is absolutely not true.

Class instances (objects) contain data members . Function members look like they're "in" the class, but that's only for scoping and such: your function code doesn't "exist" inside the type, and it certainly doesn't exist inside the object ^† .

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^{† I think it could, theoretically , in that the standard doesn't outright forbid it. But honestly, no. Just no.}

Answer 3

The code for a class exists only once.

For getting a pointer to a member function (probably what you meant by method), take a look at std::function , and for attaching the function call to different objects, take a look at std::bind .