I'ma newbie in Ruby on Rails and I don't manage to change the end of a word according to the quantity it has.
Near top of the code below, you'll see that I write
h3 "The deal has #{deal.prizes.where(:prize_type => u).count} #{u}
The "u" here takes one of the value inside an array called PRIZE_TYPE. How can I do so that
if count= 1, it displays "the deal has 1 jackpot prize"
if count=4, it displays "the deal has 4 jackpot prizeS
Note: The count can't be = 0 or < 0
Here is my code:
panel "Details of Prizes" do
PRIZE_TYPES.each do |u|
table_for deal.prizes.where(:prize_type => u) do |t|
h3 "The deal has #{deal.prizes.where(:prize_type => u).count} #{u}s
initially set in the campaign for a total value of #{custom_number_to_currency (deal.category_prizes_total_initial_value(u)) }", class: 'title-within-table'
if deal.prizes.where(:prize_type => u).count > 0 # if there is at least one record of 'jackpot prize'
t.column("Prize") { |prize| link_to( image_tag( prize.prize_image_url, class: 'main_img_in_admin_interface' ), admin_prize_path(prize), target: :blank ) }
t.column("Name") { |prize| link_to prize.prize_name, admin_prize_path(prize), target: :blank }
t.column("Category") { |prize| prize.prize_category }
t.column("Initial quantity") { |prize| prize.prize_initial_stock_quantity }
end # end of Prize.each...
end # end of panel "details of prizes"
And the PRIZE_TYPE constant:
PRIZE_TYPES = ["Jackpot prize","Consolation prize", "awesome prize"]
You could use ruby's pluralize:
prize_type.pluralize(count)
"Jackpot prize".pluralize(1)
#> Jackpot prize
"Jackpot prize".pluralize(2)
#> Jackpot prizes
Or ActiveSupport::Inflector.pluralize if you want to do the check yourself:
prize_type.pluralize
"Jackpot prize".pluralize
#> "Jackpot Prizes"
Or rails has pluralize that uses a combination Inflector and some base logic:
pluralize(count, prize_type)
pluralize(1, prize_type)
#> 1 Jackpot prize
pluralize(2, prize_type)
#> 2 Jackpot prizes
you can use the ruby instance method
http://apidock.com/rails/ActionView/Helpers/TextHelper/pluralize
"string".pluralize(count)
so for your case,
prizes_count = deal.prizes.where(prize_type: u).count
h3 "The deal has #{prizes_count} #{u.pluralize(prizes_count)}"
Use pluralize
count = deal.prizes.where(:prize_type => u).count
h3 "The deal has #{count} #{u.pluralize(count)}}"
According to pluralize
you can just do
pluralize(1, 'person')
# => 1 person
pluralize(2, 'person')
# => 2 people
pluralize(3, 'person', plural: 'users')
# => 3 users
pluralize(0, 'person')
# => 0 people
pluralize(2, 'Person', locale: :de)
# => 2 Personen
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