no matching function for getline c++

Question

I'm trying to input a number, and based on that number, the user would have to enter x amount of times.

For example

3 //how many the user wants
192 231 2 3
22192 2 1 23
2831 3 23 1

I tried doing this, but it keeps saying no matching function for getline

int* x = NULL;
int numbers;
cin >> numbers;
x = new int[numbers]

for (int i=0;i<numbers;i++)
{
    std::getline(std::cin, numbers)
    x[i] = numbers
}

Answer 1

getline的第二个参数的类型为std::string

Answer 2

You definitely do not want to use std::getline as it doesn't look like you want a string of numbers, but rather numbers themselves.

What you want is to read number by number, so use the same thing you did to read in the numbers , but do not read it in numbers again. (Because you are using it in the loop.)

Anyway, an approximation of what you want is this:

int how_many;
std::vector<int> numbers;
std::cin >> how_many;
for (int i = 0; i < how_many; i++){
    int temp;
    std::cin >> temp;
    numbers.push_back(temp);
}