I there a smarter way to define an array like this in Ruby?
array = [5, 15, 25, 35, 45, 55, 65, 75]
Thanks for any help.
5.step(75, 10).to_a #=> [5, 15, 25, 35, 45, 55, 65, 75]
Use Range#step
:
Range.new(5, 75).step(10).to_a
# => [5, 15, 25, 35, 45, 55, 65, 75]
[*Range.new(5, 75).step(10)]
# => [5, 15, 25, 35, 45, 55, 65, 75]
[*(5..75).step(10)] # (5..75) == Range.new(5, 75)
# => [5, 15, 25, 35, 45, 55, 65, 75]
Not sure if it is nicer, but one way would be:
a = 8.times.map {|i| i*10+5} #=> [5, 15, 25, 35, 45, 55, 65, 75]
The benefit of this method, is that the amount of items in the result ( 8
) is explicit.
Here is one way :
>> Array.new(8) { |i| i*10 + 5 }
=> [5, 15, 25, 35, 45, 55, 65, 75]
>>
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