How To parse extract the values present in XML node description in C#

Question

I am able to parse and extract the inner text within xml tags. I am not able to extract the values present in Job tag
My Xml file format

    <?xml version="1.0" standalone="yes"?>
    <SmPpProperties>
     <SmProperties>
       <Job Name="Job001" CreatedDate="2012-10-15T10:43:56.0972966-06:00" ModifiedDate="2012-10-       15T10:46:07.6878231-06:00">
 //            **I am not able to extract the values present in above Job tag**
         <NuclearSystem>Barium</NuclearSystem>
                      </Job>
    </SmProperties>
 <SmPpProperties>

C# code

       // Load XML Document
             XmlDocument MyDoc = new XmlDocument(); 
       // Select Node     
       MyDoc.Load(@"C:\Users\SRangarajan\Desktop\12001_.xml");

            XmlNode MyNode = MyDoc.SelectSingleNode("SmPpProperties/SmProperties/Job");
            Console.WriteLine(String.Concat("NuclearSystem: ", MyNode.InnerText));
            Console.ReadKey();

Answer 1

XmlNode.InnerText returns concatenated value of node and its child notes. That will give you Barium . Name, ModifiedDate and CreatedDate are attributes.

Your intent is not clear, but If you want to get concatenated values of all attributes:

String.Join(",", MyNode.Attributes.Cast<XmlAttribute>().Select(a => a.Value))

Or you can get value of particular attribute by name or index:

string name = MyNode.Attributes["Name"].Value;
string createdDate = MyNode.Attributes[1].Value;

NOTE: I always suggest you use Linq to Xml for parsing xml. You can easily create strongly typed object from xml:

var xdoc = XDocument.Load(@"C:\Users\SRangarajan\Desktop\12001_.xml");
XElement j = xdoc.Root.Element("SmProperties").Element("Job");
var job = new {
                Name = (string)j.Attribute("Name"),
                CreatedDate = (DateTime)j.Attribute("CreatedDate"),
                ModifiedDate = (DateTime)j.Attribute("ModifiedDate"),
                NuclearSystem = (string)j.Element("NuclearSystem")
            };

That give you job object, which will have strongly-typed properties for name, created date and modified date. And date properties will have DateTime type!

Answer 2

try to use linq , like this:

string xml = "xml";
    XDocument xdoc = XDocument.Parse(xml);
    XElement nuclear = xdoc.Descendants(document.Root.Name.Namespace + "NuclearSystem").FirstOrDefault();

    string nuclearSystem = nuclear.Value();

Answer 3

In order to get the Attributes, use the Attributes property and then access the Value:

XmlNode MyNode = MyDoc.SelectSingleNode("SmPpProperties/SmProperties/Job");
Console.WriteLine(String.Concat("Name: ", MyNode.Attributes["Name"].Value));
Console.WriteLine(String.Concat("CreatedDate: ", MyNode.Attributes["CreatedDate"].Value));
Console.WriteLine(String.Concat("ModifiedDate: ", MyNode.Attributes["ModifiedDate"].Value));
Console.WriteLine(String.Concat("NuclearSystem: ", MyNode.InnerText));