NSNumber object of type long

Question

I'm facing a wierd problem with NSNumber ,When i run the following code,

NSNumber *num = [NSNumber numberWithLong:1000];
const char* type =[num objCType];
if (strcmp (type, @encode (long)) == 0) {
    NSLog(@"Type is long");
}else if(strcmp (type, @encode (int)) == 0){
       NSLog(@"Type is int");
}

The output is :

Type is int

Edit: I tried [NSNumber numberWithLong:1000L] and [NSNumber numberWithLong:1000000000]

But still the same output.

Why is the type int here??

Answer 1

The answer is simple... the documentation for objCType says:

Special Considerations

The returned type does not necessarily match the method the receiver was created with.

Answer 2

This is like asking a stringWithInt method to return a string that still knows it is an int. You create an NSNumber , you get an NSNumber .