Vim: How can I search and replace on just part of each line?

Question

I've got a list of phrases with spaces:

Part One
Part Two
Parts Three And Four

I'd like to use Vim to process the list to produce this:

part_one,"Part One"
part_two,"Part Two"
parts_three_and_four,"Parts Three And Four"

I can get use this regex:

:%s/.*/\L\0\E,"\0"/

to get me to this, which is really close:

part one,"Part One"
part two,"Part Two"
parts three and four,"Parts Three And Four"

Is there any way to replace all spaces before the comma on each with underscores? Either as a modification of the above regex or as a second command?

Answer 1

Assuming there will never be commas in your original data, you should be able to use the following:

:%s/.*/\L\0\E,"\0"/ | %s/ \([^,]*,\)\@=/_/g

This just does another replacement after your current one to replace all of the spaces that come before a comma (using a positive lookahead).

Answer 2

:g/./let @s='"'.getline('.').'"'|s/ /_/g|exec "norm! guuA,\<ESC>\"sp"

如果我这样做，我可以用宏来做。

Answer 3

You can try with an expression in the replacement part, like:

:%s/\v^.*$/\=tolower(substitute(submatch(0), "\\s\\+", "_", "g")) . ",\"" . submatch(0) . "\""/

It first substitute all whitespaces with _ , and the returned string is lowercased. Then it joins the result with the matched line surrounded with double quotes.

It yields:

part_one,"Part One"
part_two,"Part Two"
parts_three_and_four,"Parts Three And Four"

Answer 4

From where you left off, I would split all the lines after the comma:

:%s/,/,\r/

Then you can replace the spaces on just the lines with a comma and join your lines back together:

:g/,/:s/ /_/g|j!