Regex capture only 0 to 85

Question

I want to substitute numbers from 0-85. Right now i have 0-89. subject = re.sub(r'([0-8]\\w%?)', '', subjectext)

When I do subject = re.sub(r'([0-8][0-5]%?)', '', subjectext) The regex breaks.

Answer 1

Try a pattern like this:

[1-7]?[0-9]|8[0-5]

This will match any string consisting of an optional digit from 1 to 7 followed by a digit from 0 to 9 or an 8 followed by a digit from 0 to 5.

If you need to include an optional % sign (which wasn't explicitly stated as a requirement, but your pattern seems to suggest that you might need it) use this:

([1-7]?[0-9]|8[0-5])%?

However, the above will match a string like 9 inside a larger string like 92 . If you don't want this, you might want to consider using lookarounds to make sure that the matched substring isn't preceded by or followed by another digit, like this:

(?<!\d)([1-7]?[0-9]|8[0-5])%?(?!\d)

Answer 2

这个正则表达式怎么样？

[1-7]?\d|8[0-5]

Answer 3

You want to get every number from 0 to 85, so every number start by 0-7 followed by 0-9 or 8 followed by 1, 2, 3, 4 or 5:

[1-7]?[0-9]|8[0-5]
# ^^^^^^^^^ ^^^^^^
  0 to 79  | 80 to 85

Answer 4

Consider the following Regex...

([0-7][0-9]|8[0-5])

Good Luck!