Exception handling with python

Question

Hi guys am just a beginner in python.I studied about exception handling and it found so difficult for me. My code is

def exceptionhandling(z,y):
hd = z
hs = y
try:
sd = hd/hs
except ZeroDivisionError as err
print "this cannot be possible".err

And when i called the function exceptionhandling(1,0) i didnt get the expected output "this cannot be possible".

PLease help me in understanding this one ..Am new to so so am sorry if this is a low standard one.

Answer 1

You try to call err method of string. Actually, it doesn't has it) Better way to do this is

print "this cannot be possible %s" % err.message

Also I hope that you don't forget about indentations.

Answer 2

There exists some typos in your code:

#first indent your code correctly
def exceptionhandling(z,y):
    hd = z
    hs = y
    try:
        sd = hd/hs 
        return sd #return the result if you get it without exception
    except ZeroDivisionError as err: #need ":" at the end of line
        print "this cannot be possible", err  #print multiple strings with commas

running demo:

In [59]: exceptionhandling(0, 3) #0/3 is ok 

In [60]: exceptionhandling(4, 0) #4/0 is not allowed
this cannot be possible integer division or modulo by zero

Answer 3

You will get err as exception object, you can get the detail value of that using err.args .

args is tuple of 2 element, first is code and second is description.