I have the following schema (two tables):
**APPS**
| ID (bigint) | USERID (Bigint) | USAGE_START_TIME (datetime) |
------------------------------------------------------------------
| 1 | 12 | 2013-05-03 04:42:55 |
| 2 | 12 | 2013-05-12 06:22:45 |
| 3 | 12 | 2013-06-12 08:44:24 |
| 4 | 12 | 2013-06-24 04:20:56 |
| 5 | 13 | 2013-06-26 08:20:26 |
| 6 | 13 | 2013-09-12 05:48:27 |
**USAGE**
| ID (bigint) | APPID (bigint) | DEVICEID (bigint) | HIGH_COUNT (bigint) | MEDIUM_COUNT (bigint) |
--------------------------------------------------------------------------------------------------------
| 1 | 1 | 2 | 400 | 200 |
| 2 | 1 | 3 | 200 | 100 |
| 3 | 2 | 3 | 350 | 40 |
| 4 | 3 | 4 | 2 | 400 |
| 5 | 4 | 2 | 4 | 30 |
| 6 | 5 | 3 | 50 | 300 |
Explanation:
So, there are two tables. Now I want to find the following:
Given a USERID, Get sum of HIGH_COUNT & MEDIUM_COUNT. While counting the SUM it should be taken care that: If in USAGE, same device is used more than once, then the record which has the latest info (based on APPS.USAGE_START_TIME), should be considered while calculating the sum.
For ex:
For above schema, result should be (for userid=12) :
| HIGH_COUNT (bigint) | MEDIUM_COUNT (Bigint) |
-----------------------------------------------
| 356 | 470 |
SQL Fiddle: http://sqlfiddle.com/#!2/74ae0f
If a user uses multiple APPS
on one device, this query will use the APPS
row with the highest usage_start_time
:
select a.userid
, sum(u.high_count)
, sum(u.medium_count)
from apps a
join `usage` u
on u.appid = a.id
join (
select u.device_id
, a.userid
, max(a.usage_start_time) as max_start_time
from apps a
join `usage` u
on u.appid = a.id
group by
u.device_id
, a.userid
) filter
on filter.device_id = u.device_id
and filter.userid = a.userid
and filter.max_start_time = a.usage_start_time
group by
a.userid
In your dataset, it will select usage rows 5, 3, 4
for user 12
.
I can't quite get your numbers, but something like this should work...
SELECT a.userid
, SUM(u.high_count)
, SUM(u.medium_count)
FROM apps a
JOIN `usage` u
ON u.appid = a.id
JOIN
( SELECT userid
, deviceid
, MAX(usage_start_time) max_usage_start_time
FROM apps a
JOIN `usage` u
ON u.appid = a.id
GROUP
BY userid
, deviceid
) x
ON x.userid = a.userid
AND x.deviceid = u.deviceid
AND x.max_usage_start_time = a.usage_start_time
GROUP
BY userid;
Note that usage
is a reserved word. Therefore, this is a bad name for a column (or a table). Also, note inconsistencies between your question and your fiddle.
I think not had chance to test it but
SELECT SUM(HIGH_COUNT), SUM(MEDIUM_COUNT) FROM `USAGE` INNER JOIN `APPS` ON USAGE.APPID=APPS.ID WHERE APPS.USERID=$input_user_id_to_lookup
will give you your counts.
For yoru other question (homework?) you didn't give us the full schema so we can't guess what you need doing.
Also whoever designed that db should be shot its horrible
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