PHP mysql can't insert database and error

Question

Need help here...

I receive an error code saying...

SQL Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''students' (Lastname, Firstname, Middleinitial, Course, Year, Section, Studentnu' at line 1

by the way, i put add function in php using these codes...

$Lastname = $_POST['Lastname'];
$Firstname = $_POST['Firstname'];
$Middleinitial = $_POST['Middleinitial'];
$Course = $_POST['Course'];
$Year = $_POST['Year'];
$Section = $_POST['Section'];
$Studentnumber = $_POST['Studentnumber'];
$Violation = $_POST['Violation'];
$Punishment = $_POST['Punishment'];
$Violationdate = $_POST['Violationdate'];
$Punishmentstartdate = $_POST['Punishmentstartdate'];
$CSlength = $_POST['CSlength'];
$Add = $_POST['add'];

$records = mysql_connect('localhost', 'root', '') or die(mysql_error());

mysql_select_db('records', $records);

$sql = ("INSERT INTO 'students' (Lastname, Firstname, Middleinitial, Course, Year, Section, Studentnumber, Violation, Punishment, Violationdate, Punishmentstartdate, CSlength) VALUES('$Lastname', '$Firstname', '$Middleinitial', '$Course', '$Year', '$Section', '$Studentnumber', '$Violation', '$Punishment', '$Violationdate', '$Punishmentstartdate', '$CSlength')");

$result = mysql_query($sql, $records);

if (!$result) 
die("SQL Error: ".mysql_error());

echo "Success";

thanks for the answer.... :))

Answer 1

Get rid of the quotes around students . Either use ticks or nothing at all:

$sql = ("INSERT INTO `students` (Lastname, Firstname, Middleinitial, Course, Year, Section, Studentnumber, Violation, Punishment, Violationdate, Punishmentstartdate, CSlength) VALUES('$Lastname', '$Firstname', '$Middleinitial', '$Course', '$Year', '$Section', '$Studentnumber', '$Violation', '$Punishment', '$Violationdate', '$Punishmentstartdate', '$CSlength')");

FYI, you are wide open to SQL injections .

Answer 2

Try this

$Lastname = $_POST['Lastname'];
$Firstname = $_POST['Firstname'];
$Middleinitial = $_POST['Middleinitial'];
$Course = $_POST['Course'];
$Year = $_POST['Year'];
$Section = $_POST['Section'];
$Studentnumber = $_POST['Studentnumber'];
$Violation = $_POST['Violation'];
$Punishment = $_POST['Punishment'];
$Violationdate = $_POST['Violationdate'];
$Punishmentstartdate = $_POST['Punishmentstartdate'];
$CSlength = $_POST['CSlength'];
$Add = $_POST['add'];

 $records = mysql_connect('localhost', 'root', '') or die(mysql_error());

 mysql_select_db('records', $records);


$sql = ("INSERT INTO students (Lastname, Firstname, Middleinitial, Course, Year, Section, Studentnumber, Violation, Punishment, Violationdate, Punishmentstartdate, CSlength) VALUES('$Lastname', '$Firstname', '$Middleinitial', '$Course', '$Year', '$Section', '$Studentnumber', '$Violation', '$Punishment', '$Violationdate', '$Punishmentstartdate', '$CSlength')");


  $result = mysql_query($sql, $records);

  if (!$result) 
  die("SQL Error: ".mysql_error());

  echo "Success";

Answer 3

You just have to modify you code like this!

$Lastname = $_POST['Lastname'];
$Firstname = $_POST['Firstname'];
$Middleinitial = $_POST['Middleinitial'];
$Course = $_POST['Course'];
$Year = $_POST['Year'];
$Section = $_POST['Section'];
$Studentnumber = $_POST['Studentnumber'];
$Violation = $_POST['Violation'];
$Punishment = $_POST['Punishment'];
$Violationdate = $_POST['Violationdate'];
$Punishmentstartdate = $_POST['Punishmentstartdate'];
$CSlength = $_POST['CSlength'];
$Add = $_POST['add'];

$records = mysql_connect('localhost', 'root', '') or die(mysql_error());

mysql_select_db('records', $records);

$sql = "INSERT INTO students (Lastname, Firstname, Middleinitial, Course, Year, Section, Studentnumber, Violation, Punishment, Violationdate, Punishmentstartdate, CSlength) VALUES('$Lastname', '$Firstname', '$Middleinitial', '$Course', '$Year', '$Section', '$Studentnumber', '$Violation', '$Punishment', '$Violationdate', '$Punishmentstartdate', '$CSlength')";

$result = mysql_query($sql, $records);

if (!$result) 
die("SQL Error: ".mysql_error());

echo "Success";

Answer 4

Remove the brackets around the INSERT statement as well as put the table and column names inside the backtick, change it as below

$sql = "INSERT INTO `students` (`Lastname`, `Firstname`, `Middleinitial`, `Course`, `Year`, `Section`, `Studentnumber`, `Violation`, `Punishment`, `Violationdate`, `Punishmentstartdate`, `CSlength`) VALUES('$Lastname', '$Firstname', '$Middleinitial', '$Course', '$Year', '$Section', '$Studentnumber', '$Violation', '$Punishment', '$Violationdate', '$Punishmentstartdate', '$CSlength')" ;

Since your code is too much vulnerable to SQL injection, it is better to use mysql prepared statements.Use MySQLi or PDO class to achieve it.