I have a data frame and I want to select all rows that meet a particular condition as for example !=0. I can do it for each column but it make a real long line.
df.Individual <- df.category[df.category[,10]!=0 & df.category[,9]!=0 ........ & df.category[,2]!=0, ][,1]
I would like to select a group of columns something like this, but I can not figure how!
df.category[df.category[,c(10:5)]!=0 & c(6:2)]>0 ][,1]
Thanks!
structure(list(Individual = structure(1L, .Label = c("aaa"), class = "factor"), `Class1` = 1L,
`Class2` = 0L, `Class3` = 1L, `Class4 ` = 2L, `Class5` = 3L, `Class6` = 1L, Class7 = 1L, Class8 = 1L, Class9 = 1L), .Names = c("Individual",
"Class1", "Class2", "Class3", "Class4", "Class5", "Class6", "Class7", "Class8", "Class9"), row.names = 2L, class = "data.frame")
Edit:
I need to get all the column combination. something like a for cycle. I want to have a list of Individual sorted for their class to use as factor levels on the y axis of ggplot
as an example. but here are just some combination listed and I want all the possible column combination.
df.Individual.1 <- df.category[ df.category[,10]!=0 &
df.category[,9]!=0 &
df.category[,8]!=0 ,] [,1]
df.Individual.2 <- df.category[ df.category[,10]!=0 &
df.category[,9]!=0 &
df.category[,8]<=0 ,] [,1]
df.Individual.3 <- df.category[ df.category[,10]!=0 &
df.category[,9]<=0 &
df.category[,8]!=0 ,] [,1]
df.Individual.4 <- df.category[ df.category[,10]!=0 &
df.category[,9]<=0 &
df.category[,8]<=0 ,] [,1]
unlist(list(df.Individual.1,df.Individual.2,df.Individual.3,df.Individual.4))
At the end I need a list with individual sorted for their class status. First All Class positiv, than the first class is positiv and the other are one each negative.
1 1 1
1 1 0
1 0 1
1 0 0
0 1 1
0 1 0
0 0 1
0 0 0
here an example for 3 columns. Thanks!
I would use rowSums
(much faster than an apply
loop). Here is a logical vector of rows where columns 5
through 10
only have non-zeroes:
rowSums(df.category[,c(5:10)] != 0) == (10-5+1)
or better:
rowSums(df.category[,c(5:10)] == 0) == 0
You can combine such logical vectors using &
, then use that to extract from df.category:
logical1 <- rowSums(df.category[,c(5:10)] == 0) == 0
logical2 <- rowSums(df.category[,c( 2:6)] <= 0) == 0
df.category[logical1 & logical2, ]
Edit: Your updated question is a lot more vague, maybe try something like this:
df <- df.category
classes.col <- grep("Class", colnames(df), value = TRUE)
df$Attended <- apply(df[classes.col] > 0, 1, paste, sep = "_")
split(df$Individual, df$Attended)
一种可能性:
df[apply(df[,-1]!=0,1,all),]
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