C# Dice game, 2 dice, each dice rolls 50 times

Question

I'm creating a 2 dice game rolling 100 times and giving the game statistics and it works, kind of. The problem is that the both die's total is 50 when die 1 could be like 68 and die 2 could be 32 (Dice 1: 68, Dice 2: 32). How could I accomplish that according to my code?

int[] Dice1 = new int[7];
int[] Dice2 = new int[7];

Random x = new Random();
for (int throw = 1; throw <= 50; throw++)
{
    Dice1[x.Next(1, 7)]++;
    Dice2[x.Next(1, 7)]++;
}

Console.WriteLine("Side  |  times");//How many times sides 1-6 appear.

for (int side = 1; side < Dice1.Length; side++)
{
    Console.Write("  " + side + "        ");
    Console.WriteLine(Dice1[side] + Dice2[side]);
}

int total = Dice1.Sum() + Dice2.Sum();
Console.WriteLine("~~~~~~~~~~~~~~~~~~~~~~");
Console.WriteLine("total of 1. Dice: " + Dice1.Sum());
Console.WriteLine("total of 2. Dice: " + Dice2.Sum());
Console.WriteLine("~~~~~~~~~~~~~~~~~~~~~~");
Console.Write("Total Sum: ");
Console.WriteLine(total);

OUTPUT:

http://oi60.tinypic.com/140vzid.jpg

If anyone has any idea how i can get this to work please answer, greatly appreciated.

Answer 1

Currently you're rolling 2 dice exactly 50 times (for a total of 100 die rolls). It sounds like you want to perform 100 die rolls in which each roll choses a die at random to roll. In this case, simply change your loop to loop 100 times, not 50, and instead of rolling both, choose one to roll:

for (int throw = 1; throw <= 100; throw++)
{
    if(x.Next(0,2) == 0)
        Dice1[x.Next(1, 7)]++;
    else
        Dice2[x.Next(1, 7)]++;
}