Error? Can’t Figure Out

Question

I am creating a tkinter program and ran into this weird error. Here is my code:

from Tkinter import *   
def get_info(key):     
    pass   
def create_new():  
    create = Toplevel(root)
    create.title('Create A New Contact')
    Label(create, text='Name: ').grid(row=0, sticky=W+E)
    name = Entry(create, width=8).grid(row=1, sticky=W+E)
    Label(create, text='Address(ex. 1111 Main St, MyCity, Anystate 12345): ', wrapLength=1).grid(row=2, sticky=W+E)
    address = Entry(create, width=8).grid(row=3, sticky=W+E)
def access():
    access_window = Toplevel(root)
    access_window.title("Access a Contact")
    Label(access_window, text=“Enter a first name: ‘).grid(row=0, sticky=‘W+E’)#Error here
    access_key = Entry(access_window, width=8).grid(row=0, sticky='W+E')
    Button(access_window, text="Submit", command=lambda: get_info(access_key.get('0.0', 'end-1c'))).grid(row=2, sticky='W+E')
root = Tk()
root.title('Address Book')
button1 = Button(root, text="Create New", command=create_new).grid(row=0, column=0)
button2 = Button(root, text=“Access Person”, command=access).grid(row=0, column=1)

The console says:

Error: EOL while scanning string literal.

How can I fix this?

Answer 1

This line has invalid characters:

Label(access_window, text=“Enter a first name: ‘).grid(row=0, sticky=‘W+E’)
#                       --^                  --^                   --^ --^

So does this one:

button2 = Button(root, text=“Access Person”, command=access).grid(row=0, column=1)
#                         --^           --^

In Python, string literals may only be enclosed by normal apostrophes ' or normal quotation marks " .

---

To fix the problem, replace each “ and ' with a " :

Label(access_window, text="Enter a first name: ").grid(row=0, sticky="W+E")

button2 = Button(root, text="Access Person", command=access).grid(row=0, column=1)

---

Also, the grid method of every Tkinter widget works in-place (it always returns None ). Thus, you should call it on its own line:

button2 = Button(root, text="Access Person", command=access)
button2.grid(row=0, column=1)

Answer 2

You need to use the same kind of quotation marks to mark the start and end of a string.

So the line you highlighted needs use consistent quotation marks - you shouldn't mix single and double quotes. Your line need to look like this

Label(access_window, text="Enter a first name: ").grid(row=0, sticky=‘W+E’)

Or this

Label(access_window, text='Enter a first name: ').grid(row=0, sticky=‘W+E’)

Not this, where you start with a double quote and end with a single quote

Label(access_window, text=“Enter a first name: ‘).grid(row=0, sticky=‘W+E’)