I have this variable; Furniture **furnitures; Which is an abstract baseclass to 2 subclasses, Bookcase and Couch. I add these randomly;
furnitures[n++] = new Bookcase ();
furnitures[n++] = new Couch();
.
.
For the sake of explaination. Lets set some minor variables. Furniture private: name, prize Bookcase private: size Couch private: seats
How would I go about if I wanted to print out information such as; name and seats?
There are various of problems in this issue. 1, distinguish which subclass is which when I use Furniture[i]. 2, I dont want to blend too much unneccessary functions between the two subclasses that arent needed.
class Furniture
{
virtual void output() = 0;
};
class Couch : public Furniture
{
void output() override;
};
class Bookshelf : public Furniture
{
void output() override;
};
You could define the function in Furniture to save from duplicate code in subclasses like this:
void Furniture::output()
{
// We assume here the output is to cout, but you could also pass the necessary
// stream in as argument to output() for example.
cout << name << price;
}
void Couch::output()
{
Furniture::output();
cout << seats;
}
void Bookshelf::output()
{
Furniture::output();
cout << size;
}
You should never use arrays polymorhphically . Read the first item (I think it's the first) in Scott Meyers' More Effective C++ book to find out why!
In fact, you should almost never use raw arrays in C++ anyway. A correct solution is to use a std::vector<Furniture*>
.
How would I go about if I wanted to print out information such as; name and seats?
There are various of problems in this issue. 1, distinguish which subclass is which when I use Furniture[i]. 2, I dont want to blend too much unneccessary functions between the two subclasses that arent needed..
You are facing this problem because you are abusing object-oriented programming. It's simple: object-oriented programming makes sense when different types implement an abstract common operation and the concrete type is chosen at run-time. In your case, there is no common operation. Printing (or receiving) the number seats is for one type, printing (or receiving) a size is for the other type.
That's not to say that it's bad or wrong, but it's simply not object-oriented.
Now C++ would not be C++ if it didn't offer you a dangerous tool to get out of every dead end you've coded yourself into. In this case, you can use Run-Time Type Identifcation (RTTI) to find out the concrete type of an object. Google for typeid
and dynamic_cast
and you'll quickly find the solution. But remember, using RTTI for this problem is a workaround . Review your class design, and change it if necessary.
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