How to remove all C and C++ comments in vi?
//
/*
*/
You can't. Parsing C and C++ comments is not something that regular expressions can do. It might work for simple cases, but you never know if the result leaves you with a corrupted source file. Eg what happens to this:
printf ("//\n");
The proper way is to use an external tool able to parse C. For example some compilers may have an option to strip comments.
Writing a comment stripper is also a basic exercise in lex and yacc programming.
See also this question: Remove comments from C/C++ code
With regular expressions, because of the complexity of C/C++ syntax, you will at best achieve a solution that is 90% correct. Better let the right tool (a compiler) do the job.
Fortunately, Vim integrates nicely with external tools. Based on this answer , you can do:
:%! gcc -fpreprocessed -dD -E "%" 2>/dev/null
Caveats:
gcc
Esc:%s/\/\///
Esc:%s/\/\*//
Esc:%s/\*\///
You can use a lexical analyzer like Flex directly applied to source codes. In its manual you can find " How can I match C-style comments? ".
If you need an in-depth tutorial, you can find it here ; under "Lexical Analysis" section you can find a pdf that introduce you to the tool and an archive with some practical examples, including "c99-comment-eater".
这是一个vim内联函数,可删除当前缓冲区中的所有C和C ++注释。
keepp %s/\%(\/\*\_.\{-}\*\/\)\|\/\/.*//
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