Regex: exclude lines beginning with whitespace

Question

I want to match any line starting with some arbitrary number of asterisks, followed by a whitespace and some text. For example:

** some text  

This is what I'm using:

/(\A\**)\ (.*)/

That works fine, except for the case where the line begins with a whitespace. As you can see in this example at rubular , the whitespace is the first match group and the asterisks and text are the second. All my attempts to fix it have ended up matching other, non-asterisk characters. What's the proper way to do this?

Edit: I wasn't clear: I want the match fail if the line starts with whitespace.

Answer 1

如果您的目标行需要以*开头的可选空格开头，那么您应该使用+ （表示一个或多个）而不是* （表示零或更多）与可选空格[ ]*

^[ ]*[*]+ (.*)