How to sort arrayList according to Integer size in android?

Question

I am sorting my array list int items by using "compareTo(String string);" this method comparing only string but not int values.How I can sort my array list based on integer value.

Here is my code :

 Collections.sort(mAllSpeedsArray, new AllSpeedsComparator());

public class AllSpeedsComparator implements Comparator<AllSpeeds> {

@Override
public int compare(AllSpeeds lhs, AllSpeeds rhs) {
    // TODO Auto-generated method stub      
        return lhs.getSpeed().compareTo(rhs.getSpeed());        
    }
}

Answer 1

使您的AllSpeeds数据结构从getSpeed()返回一个int （或double或其他数字getSpeed() ，或者对两个字符串使用Integer.parse(string) ，然后比较整数。

Answer 2

How about this

@Override
public int compare(AllSpeeds lhs, AllSpeeds rhs) {
    // TODO Auto-generated method stub      
    int a = Integer.parseInt(lhs.getSpeed());
    int b = Integer.parseInt(rhs.getSpeed());
    return a < b ? 1 : (a == b ? 0 : -1);
}