how to insert a datagridview value to database on button click in c#

Question

I have two controls in my winform ,that is textboxes and datagridview .textboxes data entered by user save in one table(purchase) and datagridview data entered is save in another table (purchasedetail).My problem is textboxes values are saving in purchase table but datagridview values are not saving to database.

here is my save button code:

 private void SAVE(object sender, EventArgs e)
        {

            try
            {  
                con.Open();
                cmd = new SqlCommand("insert into Purchase(purchase_id,purchase_date,ref_no,total,total_wrds) values(@purchase_id,@purchase_date,@ref_no,@total,@total_wrds)", con);

                cmd.Parameters.AddWithValue("@purchase_id", textid.Text);
                cmd.Parameters.AddWithValue("@purchase_date", dateTimePicker1.Value);
                cmd.Parameters.AddWithValue("@ref_no", textrno.Text);
                cmd.Parameters.AddWithValue("@total", texttotal.Text);
                cmd.Parameters.AddWithValue("@total_wrds", textinwrds.Text);

                cmd.ExecuteNonQuery();
                foreach (DataGridViewRow row in datagrid.Rows)
                {

                    if (!row.IsNewRow)
                    {

                           using(SqlCommand cmd11 = new SqlCommand("insert into Purchasedetail(product_id, product_name,qty,price,tax,discount,total)values(@product_id, @product_name,@qty,@price,@tax,@discount,@total)", con))

                           {
                            cmd11.Parameters.AddWithValue("@product_id", row.Cells[0].Value);
                            cmd11.Parameters.AddWithValue("@product_name", row.Cells[1].Value);
                            cmd11.Parameters.AddWithValue("@qty", row.Cells[2].Value);
                            cmd11.Parameters.AddWithValue("@price", row.Cells[3].Value);
                            cmd11.Parameters.AddWithValue("@tax", row.Cells[4].Value);
                            cmd11.Parameters.AddWithValue("@discount", row.Cells[5].Value);
                            cmd11.Parameters.AddWithValue("@total", row.Cells[6].Value);
                            cmd11.ExecuteNonQuery();
                            datagrid.Refresh();

                            //row.ReadOnly = true;
                            //clm.ReadOnly = true;
                            MessageBox.Show("Added Sucessfully", "OUTPUT", MessageBoxButtons.OK, MessageBoxIcon.Information);
                            return;
                           }

                    }



                }



            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
            }

            finally
            {
                con.Close();
            }

        }

Answer 1

I assume you want to save your DataGrid table to a table in your database. With this answer I recommend you to work with your data in datagrid, not textboxes, if it is not very necessary. First I am explaining the code. Since your temporary DG table will be "added" you need to clear it first. Then turn your itemssource into a table and it is ready to be saved. Use an adapter to update the table.

  try
                {
                    SqlCommand ClearTableCommand = new SqlCommand("delete from " + CurrentTableName + ";", myconnection);
                    ClearTableCommand.ExecuteNonQuery();
                    DataTable myDT;
                    DataView myview;
                    myview = (DataView)dataGrid1.ItemsSource;
                    myDT = myview.ToTable(CurrentTableName);



                using (SqlDataAdapter Adapter1 = new SqlDataAdapter("select * from " + CurrentTableName + "", myconnection))
                {

                    Adapter1.UpdateCommand = new SqlCommandBuilder(Adapter1).GetUpdateCommand(true);
                    Adapter1.AcceptChangesDuringFill = false;
                    Adapter1.AcceptChangesDuringUpdate = true;
                    Adapter1.Update(myDT);

                }

            }
            catch (Exception ex)
            {

                System.windows.MessageBox.Show(ex.Message);
            }