Say I have command1
which outputs this:
b05808aa-c6ad-4d30-a334-198ff5726f7c
59996d37-9008-4b3b-ab22-340955cb6019
2b41f358-ff6d-418c-a0d3-ac7151c03b78
7ac4995c-ff2c-4717-a2ac-e6870a5670f0
I also have command2
which outputs this:
b05808aa-c6ad-4d30-a334-198ff5726f7c
59996d37-9008-4b3b-ab22-340955cb6019
Is there a way to grep the output from command1
to not include any lines matched from command2
, so that the final output would look like this?
2b41f358-ff6d-418c-a0d3-ac7151c03b78
7ac4995c-ff2c-4717-a2ac-e6870a5670f0
Issue this grep
command1 | grep -vF -f <(command2)
Here,
-F
means Fixed string match*
-v
means invert match
-f
means the file with patterns
<(command)
actually creates a FIFO with that command and use it on redirection.
To get all the lines from the output of command1
that do not appear in the output of command2
:
grep -vFf <(command2) <(command1)
-f
tells grep
to use patterns that come from a file. In this case, that file is the output of command2
. -F
tells grep
that those patterns are to be treated as fixed strings, not regex. -v
tells grep
to invert its normal behavior and just show lines the lines that do not match.
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