Bash script to print file names and their sizes in the current directory

Question

I just wrote a bash script to print the size and the name of all the files in a directory. It's quite simple:

du -h *

It prints first the size of the file and then the name. But now I wonder how can I reverse the order of the output: print first the name and then the size of the file.

Any ideas?

Answer 1

du -h * | awk -v FS='\t' '{ print $2, $1 }'

它通过获取du的输出并将其发送到内联awk脚本来工作，该脚本的内容如下：对于输入中给awk每一行，打印第二列，然后打印第一列。

Answer 2

Here is a Perl based solution:

du -h *|perl -pe'/\\s(.+)/&&{$_="$1\\t$`\\n"}'

It works properly for both spaces and tabs inside of file names.