I want my c# application (which I execute on a raspberry pi) to run a bash script whenever it starts..
basically: the script is located in /etc/init.d
and is named mnw
. I want whenever my c# application starts, it should execute a part of the mnw script.
If it was written it in the terminal would look like:
cd /etc/init.d
./mnw stop
I want this to happen right at the start of public static void Main()
, I've been trying
ProcessStartInfo startInfo = new ProcessStartInfo() { FileName = "/dev/init.d/./mnw", Arguments = "stop", };
Process proc = new Process() { StartInfo = startInfo, };
proc.Start();
but it says that stop is a unexpected argument, any ideas?
While using the Process
class like in the accepted answer works, I' d like to add that there is a library called CliWrap that makes CLI calls like this much easier:
using OPs question as example:
var result = await Cli
.Wrap("/dev/init.d/mnw")
.WithArguments("stop")
.ExecuteBufferedAsync();
// result contains:
// -- result.StandardOutput (string)
// -- result.StandardError (string)
// -- result.ExitCode (int)
// -- result.StartTime (DateTimeOffset)
// -- result.ExitTime (DateTimeOffset)
// -- result.RunTime (TimeSpan)
if (result.ExitCode != 0)
Console.WriteLine("Command failed")
Thank you @Tyrrrz for this library!
I have never used ProcessStartInfo
on Mono / Linux, but have you tried calling via bash?
ProcessStartInfo startInfo = new ProcessStartInfo() { FileName = "/bin/bash", Arguments = "/dev/init.d/mnw stop", };
Process proc = new Process() { StartInfo = startInfo, };
proc.Start();
Also, there is no issues with the executable bit on mnw
?
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