Hopefully this is an easy one for experts :)
I have a column containing XML (at the bottom of this post) - the column is of ntext
datatype. Rather than displaying the entire XML string in a column, I want to shred it into multiple columns. The database is SQL Server 2008 R2. Column datatype cannot be changed (MS application DB)
I've tried multiple variations of xpath queries but I keep getting null values. Hopefully it's just the way I'm referencing it which is incorrect. Any help would be greatly appreciated as I can't get my head around XML it seems (not through lack of trying!):
XML (example from one record in the result - I've split it up for ease of reading):
<?xml version="1.0" encoding="utf-16"?>
<q1:ErrorInfo ErrorCode="1073744938" DetailedCode="0" DetailedSource="0" ExceptionDetails="" xmlns:q1="http://schemas.microsoft.com/2003/dls/GenericAgentStatus.xsd">
<q1:Parameter Name="datasourceid" Value="48c3db91-4ba9-46a5-820b-a2ab2c0733aa" />
<q1:Parameter Name="doesalertneedstroubleshootuiformoredetails" Value="False" />
<q1:Parameter Name="failurecount" Value="1" />
<q1:Parameter Name="customparameterformom" Value="86924" />
<q1:Parameter Name="datasourcename" Value="servername\database1" />
<q1:Parameter Name="protectedgroup" Value="ProtectionGroup1 Servers - servername.domain" />
<q1:Parameter Name="servername" Value="servername.domain" />
</q1:ErrorInfo>
SQL which I'm working with (null values returned):
WITH XMLNAMESPACES('http://schemas.microsoft.com/2003/dls/GenericAgentStatus.xsd' as q1)
select cast(ErrorXml as XML).value('(/q1:ErrorInfo/q1:Parameter[6]/q1:value[0]/text())[1]','varchar(MAX)') as [servername]
from
target_table
At the end of all this I would like to split out servername, protected group, datasource name.
Any pointers on where I'm going wrong would be massively appreciated.
Thanks in advance
Well unfortunatley, it seems I can't mark a comment as an answer - took a look on SO forums and this is by design. Kudos to both commentors for this post.
The solution I'm using is from har07 but I did try the solution from Marcus and that worked perfectly as well.
My reworked code now looks like this ... and works perfectly:
select cast(ls.ErrorXml as XML).value('(/q1:ErrorInfo/q1:Parameter[6]/@Value)[1]','varchar(MAX)') as [ServerName],
cast(ls.ErrorXml as XML).value('(/q1:ErrorInfo/q1:Parameter[5]/@Value)[1]','varchar(MAX)') as [ProtectedGroup],
cast(ls.ErrorXml as XML).value('(/q1:ErrorInfo/q1:Parameter[4]/@Value)[1]','varchar(MAX)') as [DataSourceName],
...
Thanks loads again - saved me so much time and sanity!
一般来说,在XPath中,您可以使用@attributeName
来选择XML属性,您可以尝试以下方式:
/q1:ErrorInfo/q1:Parameter[6]/@Value
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