This seems like it should be straightforward, but I can't figure it out.
Data source is a two column, comma delimited input file with these contents:
6,10
5,9
8,13
...
And my code is:
import numpy as np
data = np.loadtxt("data.txt", delimiter=",")
m = len(data)
x = np.reshape(data[:,0], (m,1))
y = np.ones((m,1))
z = np.matrix([x,y])
Which gives me this error:
Users/acpigeon/.virtualenvs/ipynb/lib/python2.7/site-packages/numpy-1.9.0.dev_297f54b-py2.7-macosx-10.9-intel.egg/numpy/matrixlib/defmatrix.pyc in __new__(subtype, data, dtype, copy)
270 shape = arr.shape
271 if (ndim > 2):
--> 272 raise ValueError("matrix must be 2-dimensional")
273 elif ndim == 0:
274 shape = (1, 1)
ValueError: matrix must be 2-dimensional
No amount of reshaping seems to get this to work, so I'm either missing something really simple or there's a better way to do this.
EDIT: Would have been helpful to specify the output I am looking for. Here is a line of code that generates the desired result:
In [1]: np.matrix([[5,1],[6,1],[8,1]])
Out[1]:
matrix([[5, 1],
[6, 1],
[8, 1]])
The desired output can be generated this way:
In [12]: np.array((data[:, 0], np.ones(m))).transpose()
Out[12]:
array([[ 6., 1.],
[ 5., 1.],
[ 8., 1.]])
The above is copied from ipython
and so has ipython
style prompts.
To eliminate the error, replace:
x = np.reshape(data[:, 0], (m, 1))
with:
x = data[:, 0]
The former line produces a 2-dimensional matrix and that is what causes the error message. The latter produces a 1-D array with the same data.
Or how about first turning the array into a matrix, and then change the last column to 1?
In [2]: data=np.loadtxt('stack23859379.txt',delimiter=',')
In [3]: np.matrix(data)
Out[3]:
matrix([[ 6., 10.],
[ 5., 9.],
[ 8., 13.]])
In [4]: z = np.matrix(data)
In [5]: z[:,1]=1
In [6]: z
Out[6]:
matrix([[ 6., 1.],
[ 5., 1.],
[ 8., 1.]])
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