Variable in Array won't work

Question

I've added a variable with a long sentence within an array and I have the correct syntax to separate the words. Yet when I try show array key 1,2,3,... I get the error Undefined offset .

Here is my example code:

$quote = '"'; 
$string = $quote.'asds dasddsfaf fdf
ewfejfierjfnsdafjafj sdf dwiofjwejf iosad dsfosdofjeijfmkslad f
dfsijioewjo fsdlfa'.$quote; 
$newstring = implode('", "', preg_split('/[\s]+/', $string)); 
$arrayz = array($newstring); 
echo $arrayz[2];

Echoing just $newstring gives me: "asds", "dasddsfaf", "fdf", "ewfejfierjfnsdafjafj", "sdf", "dwiofjwejf", "iosad", "dsfosdofjeijfmkslad", "f", "dfsijioewjo", "fsdlfa"

Answer 1

I think you are over complicating things. There is no need to use preg_split here. Just use explode() . Try this:

$commer = '"'; 
$string = $commer.'asds dasddsfaf fdf
ewfejfierjfnsdafjafj sdf dwiofjwejf iosad dsfosdofjeijfmkslad f
dfsijioewjo fsdlfa'.$commer;

$newstring = explode(' ', $string);

print_r($newstring);

Output:

Array
(
    [0] => "asds
    [1] => dasddsfaf
    [2] => fdf
    [3] => ewfejfierjfnsdafjafj
    [4] => sdf
    [5] => dwiofjwejf
    [6] => iosad
    [7] => dsfosdofjeijfmkslad
    [8] => f
    [9] => dfsijioewjo
    [10] => fsdlfa"
)

Edit, based on comment. This should do what you want:

$commer = '"'; 
$string = 'asds dasddsfaf fdf ewfejfierjfnsdafjafj sdf dwiofjwejf iosad dsfosdofjeijfmkslad f dfsijioewjo fsdlfa'; 

$arrayz = array();
foreach(explode(' ', $string) as $word) {
    $arrayz[] = $commer . $word . $commer;
}

print_r($arrayz);

Output:

Array
(
    [0] => "asds"
    [1] => "dasddsfaf"
    [2] => "fdf"
    [3] => "ewfejfierjfnsdafjafj"
    [4] => "sdf"
    [5] => "dwiofjwejf"
    [6] => "iosad"
    [7] => "dsfosdofjeijfmkslad"
    [8] => "f"
    [9] => "dfsijioewjo"
    [10] => "fsdlfa"
)

Answer 2

$commer = '"'; 
$string = $commer.'asds dasddsfaf fdf
ewfejfierjfnsdafjafj sdf dwiofjwejf iosad dsfosdofjeijfmkslad f
dfsijioewjo fsdlfa'.$commer; 
$arrayz = preg_split('/[\s]+/', $string); 
echo $arrayz[2];

It's also a good idea to use preg_split('/[\\s]+/', $string, -1, PREG_SPLIT_NO_EMPTY); so you won't end up with empty entries in case there are double, leading, or trailing spaces.

Answer 3

You have assigned only one element in an array therefore the size of array is only 1 ie; you can access only $arrayz[0]. Try to use in a loop until the string ends and store in concurrently. This might solve.

Answer 4

array($var) creates an array from another array (if $var is an array) or a single-element array otherwise. Since implode() returns a string from the imploded array, array($newstring) will create a single-element array that is the imploded string!