I'm trying to match a string as such:
text = "This is a #hastag"
raw(
h(text).gsub(/(?:\B#)(\w*[A-Z]+\w*)/i, embed_hashtag('\1'))
)
def embed_hashtag('data')
#... some code to turn the captured hashtag string into a link
#... return the variable that includes the final string
end
My problem is that when I pass '\\1'
in my embed_hashtag method that I call with gsub, it simply passes "\\1"
literally, rather than the first captured group from my regex. Is there an alternative?
FYI:
I'm wrapping text in h
to escape strings, but then I'm embedding code into user inputted text (ie hashtags) which needs to be passed raw (hence raw
).
It's important to keep the "#" symbol apart from the text, which is why I believe I need the capture group.
If you have a better way of doing this, don't hesitate to let me know, but I'd still like an answer for the sake of answering the question in case someone else has this question.
gsub(regex){ $1 }
instead of gsub(regex, '\\1')
/\\B#(\\w+)/i
as well h()
helper, Rails 4 will escape malicious input by default embed_hashtag(data)
instead of embed_hashtag('data')
embed_hashtag
before doing the substitution link_to(text, url)
This should do the trick:
def embed_hashtag(tag)
url = 'http://example.com'
link_to tag, url
end
raw(
text.gsub(/\B#(\w+)/i){ embed_hashtag($1) }
)
The correct way would be the use of a block here.
Example :
def embed_hashtag(data)
puts "#{data}"
end
text = 'This is a #hashtag'
raw(
h(text).gsub(/\B#(\S+)/) { embed_hashtag($1) }
)
Try last match regexp shortcut:
=> 'zzzdzz'.gsub(/d/) { puts $~[0] }
=> 'd'
=> "zzzzz"
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.