I've created a map having a vector as below:
map<int,vector<int>> mymap;
How can I sort this map according to the n th value of the vector contained by map?
You can't. You can provide a custom comparator to make the underlying data get sorted another way than the default, but this only relates to keys , not values . If you have a requirement for your container's elements to exist in some specific, value-defined order, then you're using the wrong container.
You can switch to a set
, and take advantage of the fact that there is no distinction there between "key" and "value", and hack the underlying sorting yourself:
template <std::size_t N>
struct MyComparator
{
typedef std::pair<int, std::vector<int>> value_type;
bool operator()(const value_type& lhs, const value_type& rhs)
{
return lhs.second.at(N) < rhs.second.at(N);
}
};
/**
* A set of (int, int{2,}) pairs, sorted by the 2nd element in
* the 2nd item of each pair.
*/
std::set<std::pair<int, std::vector<int>>, MyComparator<1>> my_data;
int main()
{
my_data.insert(std::make_pair(1, std::vector<int>{0,5,0,0}));
my_data.insert(std::make_pair(2, std::vector<int>{0,2,0,0}));
my_data.insert(std::make_pair(3, std::vector<int>{0,1,0,0}));
my_data.insert(std::make_pair(4, std::vector<int>{0,9,0,0}));
for (const auto& el : my_data)
std::cout << el.first << ' ';
}
// Output: 3 2 1 4
However, if you still need to perform lookup on key as well , then you're really in trouble and need to rethink some things. You may need to duplicate your data or provide an indexing vector.
If I have understood correctly you can (build) add elements to the map the following way
std::vector<int> v = { 1, 2, 3 };
std::vector<int>::size_type n = 2;
mymap[v[n]] = v;
Here is an example
#include <iostream>
#include <vector>
#include <map>
#include <algorithm>
#include <cstdlib>
#include <ctime>
int main()
{
std::srand( ( unsigned )time( 0 ) );
const size_t N = 10;
std::map<int, std::vector<int>> m;
for ( size_t i = 0; i < N; i++ )
{
std::vector<int> v( N );
std::generate( v.begin(), v.end(), []{ return std::rand() % N; } );
m[v[0]] = v;
}
for ( auto &p : m )
{
for ( int x : p.second ) std::cout << x << ' ';
std::cout << std::endl;
}
return 0;
}
The output is
0 1 7 8 1 2 9 0 0 9
1 6 3 1 3 5 0 3 1 5
3 8 0 0 0 7 1 2 9 7
5 9 5 0 7 1 2 0 6 3
6 4 7 5 4 0 0 4 2 0
7 9 8 6 5 5 9 9 4 5
8 3 8 0 5 9 6 6 8 3
9 5 4 7 4 0 3 5 1 9
Take into account that as there can be duplicated vectors (that is that have the same value of the n-th element (in my example n is equal to 0) then some vectors will not be added to the map. If you want to have duplicates then you should use for example std::multimap
Also you can build a new map according to the criteria based on an existent map.
map<int,vector<int>> mymap;
How can i sort this map according to the nth value of the vector contained by map?
That's only possible if you're prepared to use that n th value as the integer key too, as in consistently assigning:
mymap[v[n - 1]] = v;
If you're doing that, you might consider a set<vector<int>>
, which removes the redundant storage of that "key" element - you would then need to provide a custom comparison though....
If you envisage taking an existing populated map that doesn't have that ordering, then sorting its elements - that's totally impossible. You'll have to copy the elements out to another container, such as a set
that's ordered on the n th element, or a vector
that you std::sort
after populating.
You can abuse the fact a c++ map uses a tree sorted by its keys. This means that you can either create a new map, with as keys the values you wish it to be sorted on, but you can also create a vector
with references to the items in your map, and sort that vector (or the other way around: you could have a sorted vector, and use a map
to create an index on your vector). Be sure to use a multimap
in the case of duplicate keys.
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