How to Pass a PHP array to JavaScript function?
Question
First of all, this question looks a duplicate of Pass a PHP array to a JavaScript function , but I actually used the first solution of Pass a PHP array to a JavaScript function - and it doesnt seem to work:
More specifically, the php echo line in the code below seems to create erroneous js output according to console error message( Uncaught SyntaxError: Unexpected token <); the console shows created html starting with "var s1 = <br /> <font size='1'><table class='xdebug-error xe-notice' dir='ltr' border='1'..."
...while I'd expect a clean var s1 = [1,2,3,4,5,6,7,8,9] - the result I also see when I tested the echo line in ideone.com
Any idea why the echo line is creating this stuff, and how to fix this?
Related joomla php code:
<?php
// No direct access to this file
defined('_JEXEC') or die('Restricted access');
$document = JFactory::getDocument();
//add jqplot libraries
JHtml::_('jquery.framework');
JHTML::script(JUri::root() .'media/system/js/jquery.jqplot.min.js');
//$document->addStyleSheet(JUri::root() .'media/system/js/jquery.jqplot.min.css');
JHtml::stylesheet( JUri::root() . 'media/system/js/jquery.jqplot.min.css' );
JHTML::script(JUri::root() .'media/system/js/jquery.jqplot.min.css');
JHTML::script(JUri::root() .'media/system/js/jqplot.barRenderer.min.js');
JHTML::script(JUri::root() .'media/system/js/jqplot.categoryAxisRenderer.min.js');
JHTML::script(JUri::root() .'media/system/js/jqplot.pointLabels.min.js');
JHTML::script(JUri::root() .'media/system/js/jqplot.enhancedLegendRenderer.js');
JHTML::script(JUri::root() .'media/system/js/weqlib.js');
$chartvals = array(1,2,3,4,5,6,7,8,9);
?>
<head>
<script type="text/javascript">
jQuery(document).ready(function(){
var s1 = <?php echo json_encode(chartvals); ?>; //!the echo seems to create erroneous js output accoding to console(?)
plot1 = jQuery.jqplot ('chart1', [s1]); //copied from example at
}); //$(document).ready
</script>
</head>
2 answers
solution1
3 ACCPTED 2014-06-24 11:17:07
You forgot the $ to referrence the chartvals var at the json_encode() function call:
var s1 = <?php echo json_encode(chartvals); ?>;
Should be
var s1 = <?php echo json_encode($chartvals); ?>;
To not trap into this sort of mistakes again you can add error_reporting(E_ALL); to the beginning of your script and set display_errors to on in your PHP config during development.
solution2
1 2014-06-24 11:17:18
var s1 = <?php echo json_encode($chartvals); ?>; //!the echo seems to create
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