Shell Script - Unix

Question

grep "<ValidateXYZResponse" filename.log* | grep -v "<ResponseCode>000<ResponseCode>"

Above command works fine in UNIX where grep -v excludes the records having response code "000"

However, along with "000", I need to exclude the following response codes too: "404", "410", "403", "406"

I am new to unix shell script.

If anyone knows how to do it, please help. Appreciate your help. Thanks.

Answer 1

you can do (foo|bar|blah) to implement OR in regex. Like:

grep ...|grep -v '<...>\(000\|40[346]\|410\)<...>'

or

grep ...|grep -vE '<...>(000|40[346]|410)<...>'

detailed explanation about regex-alternation:

http://www.regular-expressions.info/alternation.html

Answer 2

grep "<ValidateXYZResponse" filename.log* | grep -Pv "<ResponseCode>(?:000|40[346]|410)<ResponseCode>"

• The (?:000|40[346]|410) non-capturing group in the middle gives a list of codes to exclude
• | is the alternation (OR) operator
• [346] means one character that is either 3 , 4 or 6