I have the code first model defined below.
There are two relationships between Project and TeamMember:
one-to-many - Project always has one TeamMember as Manager.
public class Project { public Guid ProjectId { get; set; } [InverseProperty("ManagedProjects"), Required] public virtual TeamMember Manager { get; set; } // 2 public virtual List<TeamMember> TeamMembers { get; set; } // 1 } public class TeamMember { public Guid TeamMemberId { get; set; } public virtual List<Project> Projects { get; set; } // 1 [InverseProperty("Manager")] public virtual List<Project> ManagedProjects { get; set; } // 2 }
This model generates the Project table definition shown below.
CREATE TABLE [dbo].[Project] (
[ProjectId] UNIQUEIDENTIFIER NOT NULL,
[Manager_TeamMemberId] UNIQUEIDENTIFIER NOT NULL,
CONSTRAINT [PK_dbo.Project] PRIMARY KEY CLUSTERED ([ProjectId] ASC),
CONSTRAINT [FK_dbo.Project_dbo.TeamMember_Manager_TeamMemberId] FOREIGN KEY
([Manager_TeamMemberId]) REFERENCES [dbo].[TeamMember] ([TeamMemberId]));
I need to extend Project with a foreign key property for Manager but can not figure out to do this.
public Guid ManagerId { get; set; } // 2
[InverseProperty("ManagedProjects")]
public virtual TeamMember Manager { get; set; } // 2
The above code does not work as it just generates a ManagerId field in the Project table. I Have tried different combinations of ForeignKey og InverseProperty without any luck.
Any suggestions?
Next code should create join table for many-to-many and 'Project' table will have foreign key on this table.
public class Project
{
public Guid ProjectId { get; set; }
public virtual TeamMember Manager { get; set; } // 2
[InverseProperty("Projects")]
public virtual List<TeamMember> TeamMembers { get; set; } // 1
}
public class TeamMember
{
public Guid TeamMemberId { get; set; }
[InverseProperty("TeamMembers")]
public virtual List<Project> Projects { get; set; } // 1
[InverseProperty("Manager")]
public virtual List<Project> ManagedProjects { get; set; } // 2
}
I think that impossible have many-to-many relationship without join table.
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