I want to get style.css
from this string using RegEx
http://domain.net/jitwp/wp-content/themes/strappress/style.css?ver=3.1.1
So far, I've tried \\/(?:.(?!\\/))
but it gets /style.css?ver=3.1.1
. I'm not sure how to ignore the query string at the end or skip the forward slash.
You can use the following regex:
[^/]+\.css
Or use \\w
which matches word characters:
\w+\.css
If I were you I would use the following regex
[\w_\-]+\.css
Because the following inludes whitespace characters
[^/]+\.css
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