I want to list the public IP addresses of my EC2 instances using Bash, separated by a delimiter (space or a new-line).
I tried to pipe the output to jq with aws ec2 describe-instances | jq
aws ec2 describe-instances | jq
, but can't seem to isolate just the IP addresses.
Can this be done by aws
alone, specifying arguments to jq
, or something else entirely?
Directly from the aws cli :
aws ec2 describe-instances \
--query "Reservations[*].Instances[*].PublicIpAddress" \
--output=text
aws ec2 describe-instances \
--filter "Name=instance-state-name,Values=running" \
--query "Reservations[*].Instances[*].[PublicIpAddress, Tags[?Key=='Name'].Value|[0]]" \
--output text
The below command would list the IP addresses of all your running EC2 instances
aws ec2 describe-instances | grep PublicIpAddress | grep -o -P "\d+\.\d+\.\d+\.\d+" | grep -v '^10\.'
Hope that answers your query...
But this works without all the errors about access:
wget -qO- http://instance-data/latest/meta-data/public-ipv4/|grep .
You can use instance metadata so you can run the following command from the ec2 instance:
curl http://169.254.169.254/latest/meta-data/public-ipv4
and it will give you the public IP of the instance. If you want the private IP, you will run
curl http://169.254.169.254/latest/meta-data/local-ipv4
aws ec2 describe-instances --query "Reservations[].Instances[][PublicIpAddress]"
参考: http : //docs.aws.amazon.com/cli/latest/userguide/controlling-output.html
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