I am following the steps mentioned in Google developers site to implement sign in and sign out in my app.
The code to add the sign-in and sign-out button as mentioned there is:
<!-- sign-in button -->
<com.google.android.gms.common.SignInButton
android:id="@+id/sign_in_button"
android:layout_width="wrap_content"
android:layout_height="wrap_content" />
<!-- sign-out button -->
<Button
android:id="@+id/sign_out_button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Sign Out"
android:visibility="gone" />
In the sample mentioned over there, the sign out button looks very different(and odd) from the sign out button.
Is this because the sign out button is not taken from com.google.android.gms
?
Is there a proper sign-out button available in com. google.android.gms
?
There is no sign-out button provided by google.
If you would like extra buttons in the same style as google's, you will need to create them yourself.
But it's a lot easier than it sounds, there are many resources provided by Google to show you how to create a button that looks just like a Google button. Take a look over here:
https://developers.google.com/+/branding-guidelines
Here is a little example I made in microsoft paint to show you the kind of stuff you can make!
You can make your button look the same as <com.google.android.gms.common.SignInButton>
, adding a predefined style to your button with the xml tag style
:
style="@style/FirebaseUI.Button.AccountChooser.GoogleButton"
Note that its a FirebaseUI style and you can put the Button text that you want.
How about : change text Sign in to Sign out.
layout.xml
<com.google.android.gms.common.SignInButton
android:id="@+id/sign_out_button"
android:layout_width="wrap_content"
android:layout_height="wrap_content" />
kotlin.kt
val signOutButton: SignInButton = findViewById(R.id.sign_out_button)
signOutButton.setSize(SignInButton.SIZE_STANDARD)
signOutButton.setOnClickListener { signOut() }
val txtLogout = signOutButton.getChildAt(0) as TextView
try {
txtLogout.setText("Sign out")
} catch (e: Exception) {
//e.printStackTrace()
}
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