Question is same with title.
How to do that?
public class Main_Activity extends Activity {
int threadCount = 0;
int mainCount = 500;
@override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.layout);
Thread t_thread = new Thread(new Runnable() {
@Override
public void run() {
for (int i=0;i<100000;i++) {
threadCount++;
}
}
}
t_thread.start();
// main thread.
// how to delay a main thread until subthread is finished?
mainCount += threadCount;
// wanted result is 100500
Log.i("MyTag", "" + mainCount);
}
}
You can use:
try{
t_thread.join();
} catch(InterruptedException e){
// something useful
}
The Thread class doc is at http://developer.android.com/reference/java/lang/Thread.html
EDIT: Just read the comments. I agree with Mike. This is the way to do what you asked, but it isn't the way to solve your problem.
Add an interface:
public interface CountingListener{
public void countingDone();
}
Then you'll need a reference to the main thread, so you can call it from your "counting" thread.
final Handler mainThread = new Handler();
This is the complete code:
public class Main_Activity extends Activity {
int threadCount = 0;
int mainCount = 500;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.layout);
final Handler mainThread = new Handler();
final CountingListener listener = new CountingListener() {
@Override
public void countingDone() {
// main thread.
// how to delay a main thread until subthread is finished?
mainCount += threadCount;
// wanted result is 100500
Log.i("MyTag", "" + mainCount);
}
};
Thread t_thread = new Thread(new Runnable() {
@Override
public void run() {
for (int i = 0; i < 100000; i++) {
threadCount++;
}
mainThread.post(new Runnable() {
@Override
public void run() {
listener.countingDone();
}
});
}
});
t_thread.start();
}
This should work, without blocking your main thread.
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