Replace Multiple New Lines in One New Line

Question

I want to replace multiple Newline characters with one Newline character, multiple spaces with a single space and Insert In to database.
so far I tried this preg_replace("/\\n\\n+/", "\\n", $text); and doesn't work !

I also do this job on the $text for formatting.

    $text = wordwrap($text,120, '<br/>', true);
    $text = nl2br($text);

Answer 1

Try using the following pattern:

/[\n\r]+/

as follows:

preg_replace( "/[\r\n]+/", "\n", $text );

Answer 2

You probably need this:

preg_replace("/(\s)+/", "$1", $input_lines);

\\s --- matches any white space character (all characters like spaces, tabs, new lines, etc)

$1 --- The first white-space char in a set. If the first is a space and the we have 3 new lines after it. We'll get only 1 space.

Alternatively you can use this:

preg_replace("/(\n)+/", "$1", $input_lines);
preg_replace("/( )+/", "$1", $input_lines);

Answer 3

尝试使用以下内容：

$text = str_replace(PHP_EOL, '', $text);

Answer 4

You need to use the correct end of line character depending on the system. PHP_EOL determines the end of line character for you.

$text = str_replace(PHP_EOL, array("\\n", "\\r\\n", "\\r"), $text);

<br /> is for HTML only

Windows uses "\\r\\n" for new line characters

Unix-based uses "\\n"

Mac (I think) uses "\\r"

Answer 5

尝试preg_replace() ：

preg_replace("/[\r\n]+/", "\n", $text);

Answer 6

Considering the spaces in the last line. $text= preg_replace( "/[\\r\\n]+\\s+/", "\\r\\n", $text );