I can't figure out php syntax

Question

I have taxonomies that i need called here,

if ( $the_tax->name == 'day' , 'drink_type') {
        $tax_output = '';
    }
    return $tax_output;
}

The above code is written wrong, The taxonomy of day works, i can not figure out how to ref a second taxonomy of drink_type. do i use a comma? or || or what () if anyone knows php syntax and can help THANKS!

Answer 1

You either need logical OR (which can be written as || (common syntax) or just OR (which is PHP specific so I rather do not recommend using) - see logical operators doc for more details. So your code should look like this:

if( ($the_tax->name == 'day') || ($the_tax->name == 'drink_type') ) {
   // at least one condition met
}

or use in_array() if you going to have more allowed names:

$names = ['day','drink_type'];
if( in_array($the_tax->name, $names) {
  // allowed name...
}

Answer 2

Separate the conditions with || (logical OR)

if ( $the_tax->name == 'day' ||  $the_tax->name == 'drink_type') {
        $tax_output = '';
}
return $tax_output;
}

Answer 3

Given what you said, the correct syntax would be :

if ( $the_tax->name == 'day' || $the_tax->name == 'drink_type') { 
// Note that you can't use id ($var == 'X' || 'Y')

Answer 4

The correct syntax uses two pipes in between your two conditions of the if statement. Like this,

$tax_output;

if ( $the_tax->name == 'day' || $the_tax->name == 'drink_type') {
    $tax_output = '';
}
return $tax_output;

I left out your ending } because as is it will throw a syntax error. If that ending bracket is supposed to be there then you should add the part of the code that contains the opening bracket as well.