I have my Code like this:
private void button3_Click(object sender, EventArgs e)
{
schema s1 = new schema(readedImage);
s1.ShowDialog();
if(s1.imgToReturn != null)
{
readedImage = s1.imgToReturn;
s1.imgToReturn = null;
}
s1.Dispose();
}
Because I am creating a new instance, i dont get the "readedImage" in the new form when calling the .ShowDialog() later. Is there a way to give the parameters in the .ShowDialog Action?
edit: this is the constructor of the shema form:
public schema(Image readedImage = null)
{
InitializeComponent();
imgToReturn = readedImage;
}
Greetings and thanks for help
I am not too sure what you mean in the question.
But I think this might help you
private void button3_Click(object sender, EventArgs e)
{
schema s1 = new schema(readedImage);
if(s1.ShowDialog() == DialogResult.OK)
{
if(s1.imgToReturn != null)
{
readedImage = s1.imgToReturn;
s1.imgToReturn = null;
}
s1.Dispose();
}
}
And in the dialog you are showing make sure to set the property DialogResult
once the user is done and everything has worked out.
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