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MySQL how to count from GROUP BY

 date | userid | companyid 12.8.14 | 1 | 1 12.8.14 | 2 | 2 12.8.14 | 3 | 1 

I had a table like above. It is easy to count how many company 1 from table with normal query.

My question is : if my query is select * from table where companyid = '1' group by date , how can i get mysql_num_row equal to 2 for company 1 and userid is 1 and 3 ?

select * from table where companyid = '1' group by date will only return me mysql_num_row equal 1 and result 12.8.14 | 1 | 1 12.8.14 | 1 | 1

You can nest a query to get the sum of company one entries and then join that nested query to an outer query:

SELECT ABB2.*, ABB1.mysql_num_row
FROM `table` AS ABB2
  JOIN 
      (SELECT companyid, COUNT(userid) AS mysql_num_row
      FROM `table`
      GROUP BY companyid) AS ABB1 ON ABB1.companyid = ABB2.companyid
WHERE ABB2.companyid = 1;

Example

try like this also

select *,(select count(*) from table1 where companyid=a.companyid) as count 
from t  as a where companyid=1

You wanted:

select date,companyid,count(*)
from table
where userid = 1
group by date,companyid

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