Since I'm not the greatest with SQL, I've run into a scenario where I must sum rows together based on their 'CtrlNo' and if the results return zero, then I do not need to display them.
I'm able to sum these records and display the results like this..
SELECT CtrlNo, SUM(Amt)/COUNT(DISTINCT CtrlNo)
FROM tContractsInTransit
GROUP BY CtrlNo
This will sum the distinct CtrlNo and the results are like this..
However, I need to update a column in the table based on where the CtrlNo has zero amt.
I have tried this..
UPDATE cit SET Paid = 'True'
FROM tContractsInTransit cit
WHERE (SELECT CtrlNo, SUM(Amt)/COUNT(DISTINCT CtrlNo)
FROM tContractsInTransit
GROUP BY CtrlNo) = 0
but receive this error..
Msg 116, Level 16, State 1, Line 5
Only one expression can be specified in the select list when the subquery is not introduced with EXISTS.
This will be the query that I use to select the records that aren't paid off..
SELECT
[CtrlNo]
,[DealNoCat]
,[RefNo]
,[tCustomer].[CustomerName]
,[tBank].BankName
,[tFIManagers].[FIName]
,[Amt]
,[Days]
,[DaysOut]
FROM
[tContractsInTransit]
INNER JOIN
tFIManagers ON tFIManagers.FIManagerID = tContractsInTransit.FIManagerID
INNER JOIN
tBank ON tBank.BankID = tContractsInTransit.BankID
INNER JOIN
tCustomer ON tCustomer.CustomerID = tContractsInTransit.CustomerID
WHERE
PFX = @PFX
AND Paid = 'false'
GROUP BY
[CtrlNo]
,[DealNoCat]
,[RefNo]
,[tCustomer].[CustomerName]
,[tBank].BankName
,[tFIManagers].[FIName]
,[Amt]
,[Days]
,[DaysOut]
I have tried removing the 'WHERE Paid = 'false' and replacing Amt int he above select statement to..
SUM(Amt)/COUNT(DISTINCT CtrlNo) AS Amt
but this returns everything.
Any ideas is greatly appreciated!
Use the HAVING-clause, which is equivalent to the WHERE-clause, but is applied outside the GROUP BY:
SELECT CtrlNo, SUM(Amt)/COUNT(DISTINCT CtrlNo)
FROM tContractsInTransit
GROUP BY CtrlNo
HAVING SUM(Amt)/COUNT(DISTINCT CtrlNo) = 0
I have found the solution and I'm posting just in case someone stumbles across this problem. The solution is fairly simple...
UPDATE tContractsInTransit
SET Paid = 'true'
FROM
tContractsInTransit cit
INNER JOIN
(SELECT CtrlNo
,SUM(Amt)/COUNT(DISTINCT CtrlNo) AS Tot
FROM tContractsInTransit
GROUP BY CtrlNo
HAVING SUM(Amt)/COUNT(DISTINCT CtrlNo) = 0) t
ON cit.CtrlNo = t.CtrlNo
This updates the paid column that returns all 0 results. Thanks to Dan for the Having clause suggestion.
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