Java jackson embedded object deserialization

Question

I have in response

{
   "item": {
     "field1": 1,
     "field2": 1,
   }
}

I want to deserialize it to Privacy class with 2 fields field1 and field2 .

A have added

objectMapper.configure(DeserializationConfig.Feature.UNWRAP_ROOT_VALUE, unwrapRootValue);

But now I receive an exception

org.codehaus.jackson.map.JsonMappingException: Root name 'item' does not match expected ('Privacy') for type [simple type, class com.myproj.Privacy]

How can I map this class to json object?

Answer 1

我找到了答案：我们必须在类中添加@JsonRootName(value = "item")注释。

Answer 2

您可以使用Flexjson反序列化反序列化