This is my current Matrix class:
template<class T>
class Matrix
{
public:
Matrix() { }
Matrix(int z, int x, int y)
{
matrix.resize(z);
for (unsigned int i = 0; i < matrix.size(); i++)
matrix[i].resize(x);
for (unsigned int i = 0; i < matrix.size(); i++)
{
for (unsigned int j = 0; j < matrix[i].size(); j++)
matrix[i][j].resize(y);
}
Fill(0);
}
int dim1() { return matrix.size(); }
int dim2() { return matrix[0].size(); }
int dim3() { return matrix[0][0].size(); }
void Fill(int n);
bool Set(int z, int x, int y, T value);
class Row
{
std::vector<std::vector<T>> m_row;
public:
Row(std::vector<std::vector<T>> row) : m_row(row) { }
class Column
{
std::vector<T> m_column;
public:
Column(std::vector<T> column) : m_column(column) { }
T& operator [] (int index) { return this->m_column[index]; }
};
Column operator [] (int index) { return Column(m_row[index]); }
};
Row operator [] (int index) { return Row(matrix[index]); }
private:
std::vector<std::vector<std::vector<T>>> matrix;
};
template<class T>
void Matrix<T>::Fill(int n)
{
for (unsigned int i = 0; i < matrix.size(); i++)
for (unsigned int j = 0; j < matrix[0].size(); j++)
for (unsigned int k = 0; k < matrix[0][0].size(); k++)
matrix[i][j][k] = n;
}
template<class T>
bool Matrix<T>::Set(int z, int x, int y, T value)
{
if (z < matrix.size() && x < matrix[0].size() && y < matrix[0][0].size())
{
matrix[z][x][y] = value;
return true;
}
else
return false;
}
everything works, except the one line commented out in the code below
Matrix<int> m(3, 10, 20);
m.Set(2, 4, 10, 42);
// m[2][4][10] = 42;
std::cout << "base layer: " << m.dim1() << std::endl;
std::cout << "layer x: " << m.dim2() << std::endl;
std::cout << "layer y: " << m.dim3() << std::endl;
std::cout << "\nm[2][4][10] = " << m[2][4][10] << std::endl;
when I do "m[2][4][10] = 42", instead of the "Set(x, x, x, x)" function, the "cout << m[2][4][10]" returns 0 instead of 42. It just doesn't make sense to me and I would really like to use the subscripting to set values.
Edit : I changed the question title to make a bit more sense.
operator [] (int index) { return ; }
The return type here designates a function that returns by-value . Thus, a copy of matrix[index]
is returned and any subsequent operations done on the return value only affect the copy but not the original object.
Invariably, the solution is to return an lvalue-reference. But that still won't help because of how you're returning the index. Row(...)
constructs a temporary instance of Row
which is separate from the Row
object you should be returning - it is actually a copy of it. There's no need to use this syntax, use return directly:
operator [] (int index) { return ; }
Note that this not only applies to this function but the one that returns Column
as well.
I looked at my code again today and realized all I need is the reference to go both ways. So I changed the Row and the Column variables to references, tested it and it worked.
class Row
{
std::vector<std::vector<T>>& m_row;
public:
Row(std::vector<std::vector<T>>& row) : m_row(row) { }
class Column
{
std::vector<T>& m_column;
public:
Column(std::vector<T>& column) : m_column(column) { }
T& operator [] (int index) { return this->m_column[index]; }
};
Column operator [] (int index) { return Column(m_row[index]); }
};
Row operator [] (int index) { return Row(matrix[index]); }
I didn't want to use pointers to avoid memory leeks, which was my initial solution and probably a bad one. I think this should be a good subscript overload.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.