I have a XML loaded from a URL like this:
WebClient client = new WebClient();
client.Encoding = Encoding.UTF8;
try
{
string reply = client.DownloadString("http://Example.com/somefile.xml");
label1.Text = reply;
}
catch
{
label1.Text = "FAILED";
}
That XML belongs to a RSS Feed. I want that label1.Text shows just the titles of that XML. How can I achieve that?
Example of label1.Text
This is my first title - This is my 2nd title - And this is my last title
var xml= XElement.Parse(reply);
label1.Text = string.Join(Environment.NewLine, xml
.Descendants()
.Where (x => !string.IsNullOrEmpty(x.Value))
.Select(x=> string.Format("{0}: {1}", x.Name, x.Value))
.ToArray());
You can load your XML into an XmlDocument and then use XPath to Get the value of each node you're targeting.
XmlDocument doc = new XmlDocument(); doc.LoadXml(reply); XmlNodeList nodes = doc.SelectNodes("//NodeToSelect"); foreach (XmlNode node in nodes) { //If the value you want is the content of the node label1.Text = node.InnerText; //If the value you want is an attribute of the node label1.Text = node.Attributes["AttibuteName"].Value; }
If you are not familiar with XPath you can always check here : http://www.w3schools.com/xpath/xpath_syntax.asp
You probably need to parse the RSS XML manually to get the title. Here is some sample code for your reference:
private static List<FeedsItem> ParseFeeds(string feedsXml)
{
XDocument xDoc = XDocument.Parse(feedsXml);
XNamespace xmlns = "http://www.w3.org/2005/Atom";
var items = from entry in xDoc.Descendants(xmlns + "entry")
select new FeedsItem
{
Id = (string)entry.Element(xmlns + "id").Value,
Title = (string)entry.Element(xmlns + "title").Value,
AlternateLink = (string)entry.Descendants(xmlns + "link").Where(link => link.Attribute("rel").Value == "alternate").First().Attribute("href").Value
};
Console.WriteLine("Count = {0}", items.Count());
foreach(var i in items)
{
Console.WriteLine(i);
}
return null;
}
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