I am trying to load below XML into SQL Server table using SSIS. Original XML:
<RESULTS>
<SEARCHRESULT RECORDS="3014">
<ROW ROWNUM="1" PKField="EntityCounter">
<COLUMN COLNUM="1" NAME="EntityCounter" DATATYPE="number">1234</COLUMN>
<COLUMN COLNUM="2" NAME="Reference ID" DATATYPE="string">5678</COLUMN>
<COLUMN COLNUM="3" NAME="Name" DATATYPE="string">XYZ</COLUMN>
<COLUMN COLNUM="4" NAME="Entity Type" DATATYPE="string">LMN</COLUMN>
</ROW>
</SEARCHRESULT>
</RESULTS>
The destination table has 4 columns: EntityCounter, ReferenceID, Name and EntityType. When I create XSD for such file, I don't get the expected output.
XML source generates four columns at the output: ROW_ID, RWONUM, PKField and SEARCHRESULT_Id.
I was able to load the data when I modified the XML as below: Modified XML:
<RESULTS>
<SEARCHRESULT RECORDS="3014">
<ROW ROWNUM="1" PKField="EntityCounter">
<EntityCounter>1234</EntityCounter>
<ReferenceID>5678</ReferenceID>
<Name>XYZ</Name>
<EntityType>LMN</EntityType>
</ROW>
</SEARCHRESULT>
</RESULTS>
When I create and use XSD for above file, XML source generates seven columns at the output: ROWNUM, PKFiled, EntityCounter, ReferenceID, Name, EntityType and SEARCHRESULT_Id.
Is it possible to generate similar output using original XML?
Thank you @MarkWojciechowicz for suggesting an option to use XSLT..! I was able to transform original xml into required format using below xslt code:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="COLUMN[@NAME]">
<xsl:element name="{concat('Col_',translate(@NAME,' ',''))}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Modified XML can be loaded using SSIS.
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