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Loop array in mysql query and for the result

I'm trying to loop a mysql query and display every result on new row. I know i'm missing some pices, do i need to SET variable in mysql instead?

$value = array(B1,B2,B3,B4);
$query = "SELECT SUM($value[0]) AS ".$value[0]."_SUM, "
    ."SUM(answer_value) AS ".$value[0]."_ANSWER_SUM "
    ."FROM questions q JOIN answers a ON q.question_id = a.question_id "
    ."WHERE $value[0]=1";

$result = mysqli_query($con, $query);

while($row = mysqli_fetch_array($result)) {
    echo "<tr><td>".$value[0]."</td>";
    echo "<td>".$row['B1_ANSWER_SUM']."</td>";  
    echo "<td>".$row['B1_SUM'] ."</td>"; 
    echo '</tr>' ;  
}

I would like to get this result:

B1 B1_ANSWER_SUM B1_SUM
B2 B2_ANSWER_SUM B2_SUM
B3 B2_ANSWER_SUM B2_SUM

You need to loop through your array and query each item in the array. See below:

$value = array('B1', 'B2', 'B3', 'B4');

foreach ($value as $v) {
    $query = "SELECT SUM($v) AS ".$v."_SUM, SUM(answer_value) AS ".$v."_ANSWER_SUM FROM questions q JOIN answers a ON q.question_id = a.question_id WHERE $v=1";

    $result = mysqli_query($con, $query);

    while($row = mysqli_fetch_array($result)) {
        echo "<tr><td>".$v."</td>";
        echo "<td>".$row[$v.'_ANSWER_SUM']."</td>";  
        echo "<td>".$row[$v.'_SUM'] ."</td>"; 
        echo '</tr>' ;  
    }
}

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