I have a dictionary in Python like this: {'c': 3, 'b': 3, 'aa': 2, 'a': 2}
and I want to print it like this:
b
c
a
aa
I need to sort the dictionary first by the second key and if there are any collisions, sort them lexicographically.
I have searched and can't find any solutions. Here is what I have already tried:
temp = {'c' : 3, 'b': 3, 'aa' : 2, 'a' : 2}
results = []
for key, value in temp.items():
results.append([key, value])
results.sort(key = operator.itemgetter(1,0), reverse = True)
for result in results:
print(result)
This doesn't work though it results in this:
c
b
aa
a
The output should be:
b
c
a
aa
I appreciate any help! (Note: using Python 3)
>>> d = {'c': 3, 'b': 3, 'aa': 2, 'a': 2}
>>> sorted(d, key=lambda key: (-d[key], key))
['b', 'c', 'a', 'aa']
-
was used to make the value make it ordered descendingly by the value.
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