List of objects to JSON with Python

Question

I have a problem converting Object instances to JSON:

ob = Object()

list_name = scaping_myObj(base_url, u, number_page)

for ob in list_name:
   json_string = json.dumps(ob.__dict__)
   print json_string

In list_name I have a list of Object instances.

json_string return, for example:

{"city": "rouen", "name": "1, 2, 3 Soleil"}
{"city": "rouen", "name": "Maman, les p'tits bateaux"}

But I would like just 1 JSON string with all the info in a list:

[{"city": "rouen", "name": "1, 2, 3 Soleil"}, {"city": "rouen", "name": "Maman, les p'tits bateaux"}]

Answer 1

You can use a list comprehension to produce a list of dictionaries, then convert that:

json_string = json.dumps([ob.__dict__ for ob in list_name])

or use a default function; json.dumps() will call it for anything it cannot serialise:

def obj_dict(obj):
    return obj.__dict__

json_string = json.dumps(list_name, default=obj_dict)

The latter works for objects inserted at any level of the structure, not just in lists.

Answer 2

Another possible solution to this problem is jsonpickle which can be used to transform any Python object into JSON (not just simple lists).

From the jsonpickle home page:

jsonpickle is a Python library for serialization and deserialization of complex Python objects to and from JSON. The standard Python libraries for encoding Python into JSON, such as the stdlib's json, simplejson, and demjson, can only handle Python primitives that have a direct JSON equivalent (eg dicts, lists, strings, ints, etc.). jsonpickle builds on top of these libraries and allows more complex data structures to be serialized to JSON. jsonpickle is highly configurable and extendable–allowing the user to choose the JSON backend and add additional backends.

Performing a transformation is simple:

import jsonpickle

class JsonTransformer(object):
    def transform(self, myObject):
        return jsonpickle.encode(myObject, unpicklable=False)

Answer 3

与@MartijnPieters的答案类似，如果您不想创建单独的函数，可以将json.dumps default参数与lambda一起使用： json.dumps(obj, default = lambda x: x.__dict__)