I want to show all distinct id_did in cc_did_use
function getdidbycc($cccard_from_sipcard){
$result = mysql_query("SELECT id_did from cc_did_use where id_cc_card='$cccard_from_sipcard'");
if ($row = mysql_fetch_array($result))
{
$text = $row['id_did'];
}
return $text;
}
I have two id_cc_card="31"
and one that value has id_dd="14"
and another one = "13"
but result just show first one.
How I can show both of them?
and after that I have another function
function get_did ($p){
$result = mysql_query("SELECT did FROM cc_did WHERE id ='$p'");
while ($row = mysql_fetch_array($result))
{
echo $row['id_did'].'<br/>';
}
}
when I run getdidbycc function , it returns two value , 13 and 14 , How I can get did numbers from this two values?
You are fetching result and checking in an if
condition which will execute only once.
if ($row = mysql_fetch_array($result))
{
$text = $row['id_did'];
}
You have to fetch the result until there is value in the resultant array. So try with while
loop like,
while($row = mysql_fetch_array($result)) // while there are records
{
$text[] = $row['id_did']; // store the result in array $text
}
return $text; // return the array
First of all try to use mysqli
or pdo
instead of mysql
otherwise you will face issues in updated version of php
As per your code $text value is gets over write due to loop so use an array something like this
if ($row = mysql_fetch_array($result)) {
$text[] = $row['id_did'];
}
return $text;
or you can just return complete data as return $row;
if ($row = mysql_fetch_array($result))
{
$text = $row['id_did'];
}
change the above line to this
while($row = mysql_fetch_array($result))
{
echo $row['id_did'].'<br/>';
}
Use a while loop like that : http://php.net/manual/en/function.mysql-fetch-array.php
Mysql fetch array returns the current element only
if ($row = mysql_fetch_array($result))
{
$text[] = $row['id_did'];
}
return $text; // returns both
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