My csv file has no column name for the first column, and I want to rename it. Usually, I would do data.rename(columns={'oldname':'newname'}, inplace=True)<\/code> , but there is no name in the csv file, just ''.
"
You can view the current dataframe using data.head()
if that returns 'Unnamed: 0'
as the column title, you can rename it in the following way:
data.rename( columns={'Unnamed: 0':'new column name'}, inplace=True )
When you load the csv, use the option 'index_col' like
pd.read_csv('test.csv', index_col=0)
index_col : int or sequence or False, default None Column to use as the row labels of the DataFrame. If a sequence is given, a MultiIndex is used. If you have a malformed file with delimiters at the end of each line, you might consider index_col=False to force pandas to not use the first column as the index (row names)
http://pandas.pydata.org/pandas-docs/dev/generated/pandas.io.parsers.read_csv.html
The solution can be improved as data.rename( columns={0 :'new column name'}, inplace=True )
. There is no need to use 'Unnamed: 0'
, simply use the column number, which is 0
in this case and then supply the 'new column name'
.
这应该有效:
data.rename( columns={0 :'Articles'}, inplace=True )
试试下面的代码,
df.columns = ['A', 'B', 'C', 'D']
usually the blank column names are named based on their index
so for example lets say the 4 column is unnamed.
df.rename({'unnamed:3':'new_name'},inplace=True)
usually it is named like this since the indexing of columns start with zero.
It has a name, the name is just ''
(the empty string).
In [2]: df = pd.DataFrame({'': [1, 2]})
In [3]: df
Out[3]:
0 1
1 2
In [4]: df.rename(columns={'': 'A'})
Out[4]:
A
0 1
1 2
It can be that the first column/row could not have a name, because it's an index and not a column/row. That's why you need to rename the index like this:
df.index.name = 'new_name'
Q: "my column has no name when I print the DataFrame it shows the column 0 only and I used this technique its not helping me, can you please suggest any other method to replace the name"
data.rename( columns={0:'new column name'}, inplace=True )
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